It is possible to determine a formula for linear sequences, i.e. sequences where the difference between successive terms is always the same.
The first differences for the number pattern
| 11 | 14 | 17 | 20 | 23 | 26 | ... |
| are | 3 | 3 | 3 | 3 | 3 |
If we look at the sequence 3n, i.e. the multiples of 3, and compare it with our original sequence
| our sequence | 11 | 14 | 17 | 20 | 23 | 26 |
|---|---|---|---|---|---|---|
| sequence 3n | 3 | 6 | 9 | 12 | 15 | 18 |
we can see easily that the formula that generates our number pattern is
If, however, we had started with the sequence
| 38 | 41 | 44 | 47 | 50 | 53 | ... |
the first differences would still have been 3 and the comparison of this sequence with the sequence 3n
| our sequence | 38 | 41 | 44 | 47 | 50 | 53 |
|---|---|---|---|---|---|---|
| sequence 3n | 3 | 6 | 9 | 12 | 15 | 18 |
would have led to the formula u_n = 3n + 35.
In the same way, the sequence
| –7 | –4 | –1 | 2 | 5 | 8 | ... |
also has first differences 3 and the comparison
| our sequence | – 7 | – 4 | – 1 | 2 | 5 | 8 |
|---|---|---|---|---|---|---|
| sequence 3n | 3 | 6 | 9 | 12 | 15 | 18 |
yields the formula u_n = 3n – 10.
From these examples, we can see that any sequence with constant first difference 3 has the formula
u_n = 3n + cwhere the adjustment constant c may be either positive or negative.
This approach can be applied to any linear sequence, giving us the general rule that:
Determine a formula for this sequence:
| 7, | 13, | 19, | 25, | 31, | ... |
First consider the differences between the terms,
| 7 | 13 | 19 | 25 | 31 | ... |
| 6 | 6 | 6 | 6 |
As the difference is always 6, we can write,
As the first term is 7, we can write down the equation:
| 7 | = 6 × 1 + c |
| = 6 + c | |
| c | = 1 |
So the formula will be,
We can check that this formula is correct by testing it on other terms, for example,
the 4th term = 6 × 4 + 1 = 25
which is correct.
Determine a formula for this sequence:
| 2, | 7, | 12, | 17, | 22, | 27, | ... |
First consider the differences between the terms,
| 2 | 7 | 12 | 17 | 22 | 27 | ... |
| 5 | 5 | 5 | 5 | 5 |
The difference between each term is always 5, so the formula will be,
The first term can be used to form an equation to determine c:
| 2 | = 5 × 1 + c |
| 2 | = 5 + c |
| c | = –3 |
So the formula will be,
Note that the constant term, c, is given by
c = first term – first difference
Determine a formula for the sequence:
28, 25, 22, 19, 16, 13, ...
First consider the differences between the terms,
| 28 | 25 | 22 | 19 | 16 | 13 | ... |
| –3 | –3 | –3 | –3 | –3 |
Here the difference is negative because the terms are becoming smaller.
Using the difference as –3 gives,
The first term is 28, so
| 28 | = –3 × 1 + c |
| 28 | = –3 + c |
| c | = 31 |
The general formula is then,
or